Difference between revisions of "Methanol to Hydrocarbons problem"

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|nz        = 3
 
|nz        = 3
 
|np        = 5
 
|np        = 5
 +
|nc        = 5
 
}}<!-- Do not insert line break here or Dimensions Box moves up in the layout...
 
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  \displaystyle \min_{\theta} &\sum\limits_{j=1}^{16} &&||y(\tau_j; \theta) - z_j||^2  \\[1.5ex]
 
  \displaystyle \min_{\theta} &\sum\limits_{j=1}^{16} &&||y(\tau_j; \theta) - z_j||^2  \\[1.5ex]
 
  \mbox{s.t.}  
 
  \mbox{s.t.}  
  & \dot{y}_1 & = &  -( 2 \theta_2 - \frac{\theta_1 y_2}{(\theta_2 + \theta_5) y_1 + y_2} + \theta_3 + \theta_4) y_1, \\
+
  & \dot{y}_1 & = &  -( 2 \theta_2 - \frac{\theta_1 y_2}{(\theta_2 + \theta_5) y_1 + y_2} + \theta_3 + \theta_4) y_1, \\[0.3cm]
  & \dot{y}_2 & = & \frac{\theta_1 y_1 (\theta_2 y_1 - y_2)}{(\theta_2 + \theta_5) y_1 + y_2} + \theta_3 y_1,  \\
+
  & \dot{y}_2 & = & \frac{\theta_1 y_1 (\theta_2 y_1 - y_2)}{(\theta_2 + \theta_5) y_1 + y_2} + \theta_3 y_1,  \\[0.3cm]
  & \dot{y}_3 & = & \frac{\theta_1 y_1 (y_2 + \theta_5 y_1}{(\theta_2 + \theta_5) y_1 + y_2} + \theta_4 y_1,  \\
+
  & \dot{y}_3 & = & \frac{\theta_1 y_1 (y_2 + \theta_5 y_1}{(\theta_2 + \theta_5) y_1 + y_2} + \theta_4 y_1,  \\[0.3cm]
  & \theta_i & \geq & 0.
+
  & \theta_i & \geq & 0 \quad i = 1,...,5.
 
\end{array}  
 
\end{array}  
 
</math>
 
</math>

Latest revision as of 09:32, 27 July 2016

Methanol to Hydrocarbons problem
Algebraic states: 3
Continuous control values: 5
Path constraints: 5

The Methanol to Hydrocarbons problem tries to determine "reaction coefficients for the conversion of methanol into various hydrocarbons." (Cite and problem taken from the COPS library)


Mathematical formulation

The problem is given by


\begin{array}{llcl}
 \displaystyle \min_{\theta} &\sum\limits_{j=1}^{16} &&||y(\tau_j; \theta) - z_j||^2   \\[1.5ex]
 \mbox{s.t.} 
 & \dot{y}_1 & = &  -( 2 \theta_2 - \frac{\theta_1 y_2}{(\theta_2 + \theta_5) y_1 + y_2} + \theta_3 + \theta_4) y_1, \\[0.3cm]
 & \dot{y}_2 & = & \frac{\theta_1 y_1 (\theta_2 y_1 - y_2)}{(\theta_2 + \theta_5) y_1 + y_2} + \theta_3 y_1,  \\[0.3cm]
 & \dot{y}_3 & = & \frac{\theta_1 y_1 (y_2 + \theta_5 y_1}{(\theta_2 + \theta_5) y_1 + y_2} + \theta_4 y_1,  \\[0.3cm]
 & \theta_i & \geq & 0 \quad i = 1,...,5.
\end{array}

Parameters

The values  z_j are measurements for the concentration for  y at time points  \tau_1, ..., \tau_{16} and initial conditions are known.

Source Code

Model descriptions are available in